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A resistor has a current of 2.8A in it when the p.d. across it is 12.0V. What will be the current in it when the voltage is reduced to 6.0V?​

1 Answer

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The current in the resistor is determined by Ohm's Law, which states that the current is equal to the voltage divided by the resistance.

I = V/R

Since the voltage has been reduced to 6.0V, we can calculate the new current as follows:

I = 6.0V/12.0V = 0.5A

Therefore, the current in the resistor when the voltage is reduced to 6.0V is 0.5A.
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