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In the figure below, m2 = 76°. Find m< 1, m<3, m<4

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Answer:*

m<1 = 76°

m<3 = 76°

m<4 = 180° - 76° = 104°

*My answer is based on the information you provided me.

Explanation:

Unfortunately, I cannot see the figure you are referring to as you didn’t provide a picture. However, I can provide a general approach to solve this problem based on the information given.

Assuming that the figure is a diagram of intersecting lines, here's a way to find the measures of angles 1, 3, and 4:

1. Angles 2 and 3 are vertical angles, which means they have the same measure. Therefore, m<3 = 76°.

2. Angles 2 and 4 are supplementary angles, which means their measures add up to 180°. Therefore, m<4 = 180° - m<2.

3. Angles 1, 2, and 4 form a straight line, which means their measures add up to 180°. Therefore, m<1 + m<2 + m<4 = 180°.

4. Substitute the given measure of m<2 and the value of m<4 found in step 2 into the equation from step 3, and solve for m<1:

m<1 + 76° + (180° - 76°) = 180°

m<1 + 104° = 180°

m<1 = 76°

Therefore, the measures of angles 1, 3, and 4 are:

m<1 = 76°

m<3 = 76°

m<4 = 180° - 76° = 104°

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