428,500 views
28 votes
28 votes
Suppose that you are 5 feet 3 inches tall and cast a shadow 10 feet 6 inches long. If you are standing nextto a tree that casts a shadow that is 52 feet long, about how tall is the tree?

User Groxan
by
2.5k points

1 Answer

21 votes
21 votes

Let be "x" the height in feet of the tree.

First, we need to make the conversion from inches to feet. Since:


1\text{ ft=12 in}

We have:


\begin{gathered} (3\text{ in)(}\frac{1\text{ ft}}{12\text{ in}})=0.25\text{ ft} \\ \\ (6\text{ in)(}\frac{1\text{ ft}}{12\text{ in}})=0.5\text{ ft} \end{gathered}

Then your height is:


5\text{ ft+0.25 ft= 5.25 ft}

And your shadow is:


10\text{ f+ 0.5 ft=10.5 ft}

Knowing that, we can set up the following proportion:


(5.25)/(10.5)=(x)/(52)

Solving for "x", we get:


\begin{gathered} ((5.25)/(10.5))(52)=x \\ x=\text{ 26} \end{gathered}

Therefore, the height of the tree is about 26 feet.

Suppose that you are 5 feet 3 inches tall and cast a shadow 10 feet 6 inches long-example-1
User Cannatown
by
3.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.