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If the temperature is constant, what change in volume would cause the pressure of an enclosed gas to be reduced to one quarter of its original value?

User JBS
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1 Answer

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Answer:

Step-by-step explanation:

From ideal gas equation PV=nRT

n is the number of moles, R is the gas constant = 0.0821 atm•L/mol•K

Since temperature is constant, P1V1=P2V2

P1V1=P1/4*V2

V2=4V1

Volume of the gas must be increased 4 times

User DRobertE
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