203k views
4 votes
Calculate the force of gravity on the 0.70- kg mass if it were 1.9×10^7 m above Earth's surface (that is, if it were four Earth radii from Earth's center).

User Kovo
by
7.7k points

1 Answer

5 votes

Answer:

This answer his answers is quite long but here's your answer

Step-by-step explanation:

The force of gravity on an object depends on two factors: the mass of the object and the distance between the object and the center of the Earth. The formula to calculate the force of gravity is:

F = G * (m1 * m2) / r^2

where F is the force of gravity, G is the gravitational constant (6.67 x 10^-11 N m^2/kg^2), m1 is the mass of the first object (in this case, the mass of the Earth), m2 is the mass of the second object (0.70 kg), and r is the distance between the centers of the two objects (in this case, the distance between the center of the Earth and the 0.70 kg mass, which is 4 times the radius of the Earth, or 4 * 6,371 km = 25,484 km).

First, we need to convert the distance from meters to kilometers:

1.9 x 10^7 m = 19 x 10^6 m = 19,000 km

So, the distance between the center of the Earth and the 0.70 kg mass is 25,484 km - 19,000 km = 6,484 km.

Now we can plug in the values into the formula:

F = G * (m1 * m2) / r^2

F = (6.67 x 10^-11 N m^2/kg^2) * (5.97 x 10^24 kg * 0.70 kg) / (6,484 km * 1000 m/km)^2

F = 2.17 x 10^-1 N

Therefore, the force of gravity on the 0.70 kg mass if it were 1.9 x 10^7 m above Earth's surface would be approximately 0.217 N.

User Abdullah Nehir
by
7.4k points