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If the area of a rectangle with width x can be represented with the expression A(x) = x(14 – x), what is the perimeter of the rectangle?

A
28

B
56

C
56 – 4x

D
4x + 28

User Lakshan
by
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1 Answer

4 votes

Answer: D

Explanation:

To find the perimeter of the rectangle, we need to know both the length and width of the rectangle. Since we are given the expression for the area, which is A(x) = x(14 – x), we can use this expression to find the length of the rectangle that corresponds to a given width x.

The area of a rectangle is equal to its length multiplied by its width. So we have:

A(x) = x(14 – x)

We can rewrite this equation as a quadratic equation in standard form:

A(x) = -x^2 + 14x

To find the maximum value of A(x), we can use the formula for the x-coordinate of the vertex of a quadratic function:

x = -b / 2a

where a = -1 and b = 14 in this case.

x = -14 / 2(-1) = 7

So the maximum area occurs when the width of the rectangle is 7.

To find the length of the rectangle, we can substitute x = 7 into the expression for the area:

A(7) = 7(14 – 7) = 49

So the length of the rectangle is 49/7 = 7.

Now we can find the perimeter of the rectangle by using the formula:

P = 2(l + w)

where l is the length and w is the width.

Substituting l = 7 and w = x, we get:

P = 2(7 + x)

So the correct answer is (D) 4x + 28.

User Brandon Watson
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6.9k points