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Which graph represents the linear equation y = −5x − 4?

a graph of a line that passes through the points negative 2 comma 5 and 0 comma negative 3
a graph of a line that passes through the points negative 4 comma negative 1 and 0 comma negative 2
a graph of a line that passes through the points negative 1 comma 1 and 0 comma negative 4
a graph of a line that passes through the points negative 4 comma 3 and negative 2 comma negative 3

User Borisstr
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2 Answers

2 votes

Answer:

The linear equation y = -5x - 4 has a slope of -5 and a y-intercept of -4. Therefore, the correct graph should be a straight line with a slope of -5 and a y-intercept of -4.

Out of the four given options, the graph of a line that passes through the points (-1, 1) and (0, -4) represents the linear equation y = -5x - 4. To see why, we can use the two given points to find the slope of the line:

slope = (change in y) / (change in x) = (-4 - 1) / (0 - (-1)) = -5

The y-intercept is -4, so the equation of the line can be written in slope-intercept form as y = -5x - 4.

Therefore, the graph that represents the linear equation y = -5x - 4 is the graph of a line that passes through the points (-1, 1) and (0, -4).

Explanation:

User Nicojo
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7.8k points
4 votes

The linear equation y = -5x - 4 has a slope of -5 and a y-intercept of -4. Therefore, the correct graph should be a straight line with a slope of -5 and a y-intercept of -4.

Out of the four given options, the graph of a line that passes through the points (-1, 1) and (0, -4) represents the linear equation y = -5x - 4. To see why, we can use the two given points to find the slope of the line:

slope = (change in y) / (change in x) = (-4 - 1) / (0 - (-1)) = -5

The y-intercept is -4, so the equation of the line can be written in slope-intercept form as y = -5x - 4.

Therefore, the graph that represents the linear equation y = -5x - 4 is the graph of a line that passes through the points (-1, 1) and (0, -4).

User Aniket Jha
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8.7k points