12. When 3a2-7a+6 is subtracted from 4a²-3a +4, the result is (1) a² +4a-2 (2) a²-10a-2 (3)-a²-4a+2 (4) 7a²-10a+10

asked Jun 12, 2024 28.2k views

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12. When 3a2-7a+6 is subtracted from 4a²-3a +4, the result is

(1) a² +4a-2
(2) a²-10a-2
(3)-a²-4a+2
(4) 7a²-10a+10

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Answer:

(1) a² +4a-2

Explanation:

$4a^2-3a\:+4\:-\:\left(3a^2-7a+6\right)\\\\= 4a^2-3a\:+4\:- 3a^2 + 7a -6$

Grouping like terms

$(4a^2 -3a^2) +(-3a + 7a) +(4 - 6)\\\\= a^2 +4a - 2$

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