Question

Somebody please help :Write an equation that is perpendicular to x - 3y = 3 and passes through the point (5, -9) in

in with test.
Oy = 3x - 6
Oy=-3x + 6
O y = 1/3 x + 1
Oy=1/3x -1

Answer 1

y = - 3x + 6

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

x - 3y = 3 ( subtract x from both sides )

- 3y = - x + 3 ( divide through by - 3 )

y =
`(1)/(3)` x - 1 ← in slope- intercept form

with slope m =
`(1)/(3)`

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/((1)/(3) )` = - 3 , then

y = - 3x + c ← is the partial equation

to find c substitute (5, - 9 ) into the partial equation

- 9 = - 3(5) + c = - 15 + c ( add 15 to both sides )

6 = c

y = - 3x + 6 ← equation of perpendicular line