Answer:
27.27% of the students with scolarship are seniors.
Explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
![P(B|A) = (P(A \cap B))/(P(A))](https://img.qammunity.org/2022/formulas/mathematics/college/r4cfjc1pmnpwakr53eetfntfu2cgzen9tt.png)
In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Has scolarship
Event B: Is a senior
15% are senior, and of those, 40% have scolarship. So
![P(A \cap B) = 0.15*0.4 = 0.06](https://img.qammunity.org/2022/formulas/mathematics/college/efjtzgqkb2y03m3y8drhmaqem6ve535cus.png)
Probability of a scolarship:
15% of 40%(seniors)
30% of 25%(juniors)
20% of 25%(sophmores).
10% of 35%(freshmen). So
![P(A) = 0.15*0.4 + 0.3*0.25 + 0.2*0.25 + 0.1*0.35 = 0.22](https://img.qammunity.org/2022/formulas/mathematics/college/psq6ey5rg4wcj13ac512yz2fzp2mjjkcv1.png)
Percentage:
![P(B|A) = (P(A \cap B))/(P(A)) = (0.06)/(0.22) = 0.2727](https://img.qammunity.org/2022/formulas/mathematics/college/abi7zxoj07kgxw5egip01x7tadojl95v0u.png)
0.2727*100 = 27.27%
27.27% of the students with scolarship are seniors.