Answer: the amount of polonium remaining in the sample 1104 days later is approximately 0.12 g, and the answer is C
Explanation:
To determine how many half-lives of polonium-210 occur in 1104 days, we can divide 1104 by the half-life of 138 days:
1104 / 138 ≈ 8
Therefore, there are approximately 8 half-lives of polonium-210 in 1104 days.
To determine how much polonium is in the sample 1104 days later, we can use the fact that the amount of polonium remaining after n half-lives is given by:
Amount remaining = initial amount × (1/2)^n
where n is the number of half-lives that have occurred.
In this case, we know the initial amount is 30 g and the number of half-lives is 8. So we can calculate the amount of polonium remaining as:
Amount remaining = 30 g × (1/2)^8 ≈ 0.117 g ≈ 0.12 g (rounded to two decimal places)
Therefore, the amount of polonium remaining in the sample 1104 days later is approximately 0.12 g, and the answer is C.