Question

Can I Plss get some help on this 17&20 plss

Answer 1

(17) We want to find the area of the triangle. We need to find the base of this triangle, Let the base be b, Using the Pythagoras theorem (since it is a right-triangle), we have

`\begin{gathered} hyp^2=opp^2+adj^2 \\ (4√(11))^2=b^2+4^2 \\ 16*11=b^2+16 \\ 176=b^2+16 \\ b^2=176-16 \\ b=√(160) \\ b=4√(10) \end{gathered}`

We have gotten the base.

The area of the triangle becomes

`\begin{gathered} Area=(1)/(2)* base* height \\ A=(1)/(2)*4√(10)*4 \\ A=2√(10)*4 \\ A=8√(10) \end{gathered}`

Hence the answer is

`8√(10)`