Answer with Explanation:
The balanced chemical equation for the reaction of water (H2O) to produce oxygen gas (O2) is:
2 H2O → 2 H2 + O2
From the equation, we see that 2 moles of water react to produce 1 mole of oxygen gas. We can use this information, along with the molar mass of water and oxygen, to calculate the amount of oxygen produced when 22.7 grams of water is reacted.
The molar mass of water is 18.015 g/mol, so 22.7 grams of water is:
22.7 g / 18.015 g/mol = 1.259 mol H2O
According to the balanced chemical equation, 2 moles of water produce 1 mole of oxygen gas. Therefore, the number of moles of oxygen produced is:
1.259 mol H2O × (1 mol O2 / 2 mol H2O) = 0.630 mol O2
The molar mass of oxygen gas is 32.00 g/mol, so the mass of oxygen produced is:
0.630 mol O2 × 32.00 g/mol = 20.16 g O2
Therefore, when 22.7 grams of water is reacted, 20.16 grams of oxygen gas is produced.