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A 50kg crate slides along the floor for 10s before stopping. If it was initially moving with a velocity of 12m/s, what is the force of friction?

User Mouhamadou
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1 Answer

6 votes

Answer:

acceleration = -1.2 m/s^2

Step-by-step explanation:

We can use the equation of motion for constant acceleration to solve this problem. When the crate slides along the floor, there is a force of friction acting on it, which opposes its motion. The force of friction can be found using the following equation:

force of friction = mass x acceleration

We can use the kinematic equation to find the acceleration of the crate:

velocity = initial velocity + acceleration x time

Rearranging this equation, we get: acceleration = (velocity - initial velocity) / time

Plugging in the values we have: acceleration = (0 m/s - 12 m/s) / 10 s

Simplifying, we get: acceleration = -1.2 m/s^2

User Chris Simon
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