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What is the standard heat of reaction for the following reaction? Zn(s) Cu2+(aq) ------------ Zn2+(aq) Cu(s) (AHfo for Cu2+ = 64.4 kJlmol; AHfo for Zn2+= -152.4klmol) a. 216.8 kJ absorbed per mole b. 88.0 kJ absorbed per mole c. 88.0 kJ released per mole d. 216.8 kJ released per mole

User Vervious
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To calculate the standard heat of reaction for the given reaction, we need to use the standard enthalpy of formation values for the products and reactants.

The reaction can be written as:

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

The standard enthalpy of reaction (ΔHºrxn) can be calculated using the following formula:

ΔHºrxn = ΣnΔHºf(products) - ΣnΔHºf(reactants)

where Σn is the sum of the stoichiometric coefficients of the products or reactants.

Substituting the given values, we get:

ΔHºrxn = [ΔHºf(Cu) + ΔHºf(Zn2+)] - [ΔHºf(Cu2+) + ΔHºf(Zn)]

= [0 kJ/mol + (-152.4 kJ/mol)] - [64.4 kJ/mol + 0 kJ/mol]

= -216.8 kJ/mol

The negative sign indicates that the reaction is exothermic and releases heat.

Therefore, the standard heat of reaction for the given reaction is 216.8 kJ released per mole. Answer: d.
User Garvin
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