73.9k views
3 votes
In ΔMNO, m = 8.5 inches, m∠N=52° and m∠O=23°. Find the length of o, to the nearest 10th of an inch.

User Thyag
by
7.5k points

1 Answer

3 votes

Answer:

3.4 inches

Explanation:

You want the length of side o in ∆MNO with N = 52°, O = 23°, and m = 8.5 inches.

Law of Sines

The law of sines tells you the side lengths of a triangle are proportional to the sine of the opposite angle:

o/sin(O) = m/sin(M)

In order to make use of this relationship, we need the value of angle M.

M +N +O = 180°

M =52° +23° = 180°

M = 105° . . . . . . . . . . subtract 75°

Now, we can find the length o:

o = m·sin(O)/sin(M) = (8.5 in)·sin(23°)/sin(105°) ≈ 3.4384 in

The length of o is about 3.4 inches.

In ΔMNO, m = 8.5 inches, m∠N=52° and m∠O=23°. Find the length of o, to the nearest-example-1
User Imran Khan
by
7.7k points