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An airplane is flying on a bearing of 110 degrees 560 mph. Find the component form of the velocity of the airplane?

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To find the component form of the velocity of the airplane, we need to resolve the velocity vector into its horizontal and vertical components.

Assuming that the bearing of 110 degrees is measured clockwise from the North, the horizontal component of the velocity is given by:

cos(110 degrees) = -sin(20 degrees) ≈ -0.342

Horizontal component = 560 mph * (-0.342) ≈ -191.5 mph

Similarly, the vertical component of the velocity is given by:

sin(110 degrees) = cos(20 degrees) ≈ 0.940

Vertical component = 560 mph * 0.940 ≈ 526.4 mph

Therefore, the component form of the velocity of the airplane is approximately (-191.5 mph, 526.4 mph).

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