Question

A plate revolves about its center on a spindle with an angular velocity W = 2.0 rad/s. What is the linear velocity ofa point that is 0.032 m from the axis of rotation?

Answer 1

v: linear velocity

W: angular velocity

r: radius, or distance from center

v = rW

At 0.032m away from the center, the circumference is equal to 2*pi*0.032 m. Since W is 2 rad/s, the linear velocity is 2*pi*0.032 * (2/2*pi) = 0.032*2

v = (0.032m)(2rad/s) = 0.064 m/s