Question

Determine algebraically the co-ordinate of the points of intersection of the graphs of x-y=3 and xy=28​

Answer 1

Explanation:

First write X - Y = 3 as X = 3 +Y.

Then, replace the value of X in the equation XY = 28.

That is, (3 + Y)Y = 28.

Then, we have
`Y^(2) +3Y-28=0`. By solving for Y, we have

Y = 4 and Y = -7. Then, replecing Y in the equation X - Y = 3. We have,

X = 7 and X = -4.

Hence, the points of interseccion are, (7,4) and (-4,7)