Question

Hector is considering joining a video game service in which you can rent different video games. Hector has two options:

Option 1: requires a monthly fee of $7.50 and then $3.50 per game rental fee.
Option 2: provides the following chart to show rental fees
Number of Games Rental Fee
3 $16.50
6 $33.00
9 $49.50
12 $66.00
If x is the number of games and y is the rental fee, write an equation for both of the relationships in the form .

Option 1: y = x +

Option 2: y = x +



If Hector wants to rent 5 video games this month, use substitution to find which option would be the least expensive, Option 1 or Option 2.

Answer 1

Option 1: y = 3.50x + 7.50, Option 2: y = 16.50(x/3). Option 1 would be the least expensive option for renting 5 video games.

Step-by-step explanation:

To write an equation for Option 1, we can use the formula y = mx + b, where m represents the rental fee per game and b represents the initial fee. In this case, the rental fee per game is $3.50, so the equation would be y = 3.50x + 7.50.

For Option 2, we can use the given chart to create an equation. Since the rental fee increases by $16.50 each time the number of games rented increases by 3, we can determine that the equation is y = 16.50(x/3).

To determine which option would be the least expensive for renting 5 video games, we can substitute x = 5 into both equations and compare the values of y.

For Option 1: y = 3.50(5) + 7.50 = $24.50

For Option 2: y = 16.50(5/3) = $27.50

Therefore, Option 1 would be the least expensive option for renting 5 video games.