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Dominique is selling merchandise for a school fundraiser. She is selling calendars for $8 each and coffee mugs for $10 each. She must sell at least $600 of merchandise, including at least 40 calendars, to meet her goals.

If x represents the number of calendars and y represents the number of mugs, which system of inequalities represents this scenario?

A) 8x + 10y > 600 and y > 40
B) 8x + 10y > 600 and x > 40
C) 8x + 10y ≥ 600 and y ≥ 40
D) 8x + 10y ≥ 600 and x ≥ 40

1 Answer

5 votes

Answer:

A) 8x + 10y > 600 and y > 40

Explanation

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