Problem Below is a right triangle △ � � � △MNOtriangle, M, N, O where � � = � MO=aM, O, equals, a, � � = � ON=bO, N, equals, b, and � � = � MN=cM, N, equals, c. An altitude � � ‾ OP start overline, O, P, end overline is constructed so � � = � MP=xM, P, equals, x and � � = � PN=yP, N, equals, y. Triangle M N O where no angles are congruent. Side M O is A units long. Side O N is B units long. Side N M is C units long. Point P lies on side N M so that segment O P is the altitude of the triangle, segment M P is X units long, and segment P N is y units long. Angle O is a right angle. Triangle M N O where no angles are congruent. Side M O is A units long. Side O N is B units long. Side N M is C units long. Point P lies on side N M so that segment O P is the altitude of the triangle, segment M P is X units long, and segment P N is y units long. Angle O is a right angle. Below is the proof of the Pythagorean theorem, that � 2 + � 2 = � 2 a 2 +b 2 =c 2 a, squared, plus, b, squared, equals, c, squared. The proof is divided into three parts, where the title of each part indicates its main purpose. Complete part A of the proof. Part A: Prove � 2 = � ⋅ � a 2 =c⋅x