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What is the slope-intercept equation of the line containing the points (-5, 22) and (4, 49)? A_ y = 3x − 37 B y = 3x +37 C y = -3x - 37 D y = -3x + 37​

1 Answer

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Answer:

y = 3x + 37

Explanation:

Let's look for an equation of the form y=mx+b, whre m is the slope and b is the y-intercept (the value of y when x = 0). The slope, m, can be calculated from the two given points: (-5,22) and (4,49).

Slope is defined as the Rise/Run of the line. That is, how much the line rises (or falls) per unit change in the run, or x value. Take the two points and calculate the Rise and Run:

From (-5,22) to (4,49)

Rise is (49 - 22) or 27 [The final value minus the initial value of y].

Run is (4 - (-5)) = 9 [The final value miuns the initial value of y].

Slope is Rise/Run or 27/9 = 3; m = 3

So we can write y = 3x +b

We need to find a value of b that forces the line through the two points. Easy: Just enter one of the points in the equation we have thus far, and solve for b:

y = 3x +b

22 = 3(-5) +b for (-5,22)

22 = -15 + b

b = 37

The equation becomes y = 3x + 37.

See the attached graph.

What is the slope-intercept equation of the line containing the points (-5, 22) and-example-1
User Trey Copeland
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