Question

Can someone help me answer this

Answer 1

Step-by-step explanation:
`2x^(2) +3x+5=0\\\\x=-3±\sqrt{b^(2)-4ac} /2a\\x=-3±√(3^2-4*2*5/2*2)\\\\x=-3/4 ± √(31) * (1/4*i)\\x=-3/4 + √(31) * (-1/4*i)\\`

Answer: Using the Quadratic Formula, the answer would be x = -3/4 + \sqrt{31} * ([-]1/4*i)