Question

Write a loop that counts the number of digits that appear in the string referenced by my_string

write in python

Answer 1

Here's an example of a loop in Python that counts the number of digits that appear in a string:

my_string = "Hello world! 123"

count = 0

for char in my_string:

if char.isdigit():

count += 1

print("The number of digits in the string is:", count)

This code initializes a variable count to 0 and then loops through each character in my_string. For each character, it checks if it is a digit using the isdigit() method. If the character is a digit, it increments the count variable. Finally, it prints the total count of digits in the string.

You can replace the string "Hello world! 123" with your own string to count the number of digits in that string.

Answer 2

Here's an example code that uses a loop to count the number of digits in a string referenced by the variable my_string:

my_string = "abc123def456ghi789"

digit_count = 0

for char in my_string:

if char.isdigit():

digit_count += 1

print("Number of digits:", digit_count)

In this code, we first define the my_string variable to hold a string containing a mix of characters and digits.

We then initialize the digit_count variable to 0, which will keep track of the number of digits found in the string.

The loop iterates over each character in my_string. For each character, we check if it is a digit using the isdigit() method. If it is a digit, we increment the digit_count variable by 1.

After the loop completes, we print out the final value of digit_count, which represents the total number of digits found in the string.