Answer:
The point-slope form of a linear equation is:
y - y1 = m(x - x1)
where m is the slope of the line, and (x1, y1) is a point on the line.
In this case, the slope of the line is 4, and the line passes through the point (-1, -8). Substituting these values into the point-slope form, we get:
y - (-8) = 4(x - (-1))
Simplifying the right side of the equation, we get:
y + 8 = 4(x + 1)
Expanding the right side, we get:
y + 8 = 4x + 4
Subtracting 8 from both sides, we get:
y = 4x - 4
So the linear equation for the line with a slope of 4 and going through the point (-1, -8) is y = 4x - 4.