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Find the gradient of the straight line whose equation is 3y+x=5

User Lazy
by
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1 Answer

2 votes

Answer:

gradient = -
(1)/(3)

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

given

3y + x = 5 ( subtract x from both sides )

3y = - x + 5 ( divide through by 3 )

y = -
(1)/(3) x +
(5)/(3) ← in slope- intercept form

with gradient m = -
(1)/(3)

User Burtlo
by
7.8k points

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