Answer:
C
Explanation:
we can use the quadratic formula, which states that the roots of the equation ax^2 + bx + c = 0 are given by:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
In this case, a = -10, b = 12, and c = -9. Substituting these values into the formula, we get:
x = (-12 ± sqrt(12^2 - 4(-10)(-9))) / 2(-10)
x = (-12 ± sqrt(144 - 360)) / (-20)
x = (-12 ± sqrt(-216)) / (-20)
The expression under the square root is negative, so we can simplify it as follows:
sqrt(-216) = sqrt(216) * sqrt(-1) = 6sqrt(6)i
Substituting this back into the equation for x, we get:
x = (-12 ± 6sqrt(6)i) / (-20)
x = (3/5) ± (3sqrt(6)i)/10
Therefore, the roots of the equation are:
x = 3/5 + (3