Question

Three times the sum of a number and 16 is at most -28. Use the variable B for the unknown number

Answer 1

-25.333...

Explanation:

"A number times its sum and 16 is at most -28" can be expressed as:.

`3(B + 16) ≤ -28.`

Simplifying the equation:

`3B + 48 ≤ -28.`

48 from both sides subtracted results in:

`3B ≤ -76.`

Multiplying both sides by 3, we get:

`B ≤ -25.333...`

Thus, the answer is:

`B ≤ -25.333...`

Consequently, any value B that is less than or equal to -25.333. will eliminate the inequality stated.

Answer 2

3 × (16 + B) = <-28

Explanation:

An equation you can use to solve for this is:

• 3 × (16 + B) = <-28

Therefore, you can use this equation to solve for three times the sum of a number and 16 is at most -28.