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Use models of a sphere, cylinder, and two cones. The sphere and cylinder have the same diameter and height. The cones have the same diameter and half the height of the sphere. Describe the relationship between the volumes of these shapes.​

User Joliejuly
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Answer:

Explanation:

Let's assume that the diameter and height of the sphere and cylinder are both equal to "d" units, and the diameter and half-height of each cone are also equal to "d" units.

The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius. Since the diameter of the sphere is "d," the radius is d/2, so we can simplify the formula to V_sphere = (4/3)π(d/2)^3.

The formula for the volume of a cylinder is V = πr^2h, where r is the radius and h is the height. Since the diameter and height of the cylinder are both "d," the radius is also d/2, so we can simplify the formula to V_cylinder = π(d/2)^2d.

The formula for the volume of a cone is V = (1/3)πr^2h. Since the diameter and half-height of each cone are both "d," the radius is d/2, and the height is d/2. So we can simplify the formula to V_cone = (1/3)π(d/2)^2(d/2).

Now, let's compare the volumes of these shapes.

V_sphere/V_cylinder = [(4/3)π(d/2)^3]/[π(d/2)^2d] = (4/3)(d/2)/(d/2) = 4/3

V_cone/V_sphere = [(1/3)π(d/2)^2(d/2)]/[(4/3)π(d/2)^3] = (1/3)/(4/3)(d/2) = 1/4

Therefore, the ratio of the volume of the sphere to the volume of the cylinder is 4/3, and the ratio of the volume of the cone to the volume of the sphere is 1/4.

In other words, the volume of the sphere is 4/3 times the volume of the cylinder, and the volume of the cone is 1/4 times the volume of the sphere.