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How do you put this in a system of equation
2y-x=6
3y-x=4

1 Answer

2 votes

Answer: The system of equations would be:

2y - x = 6

3y - x = 4

With the answer of X being -10 and Y= -2

Explanation:

Add x to both sides:

2y = x + 6

Subtract 6 from both sides:

2y - 6 = x

Now we can substitute this expression for x into the second equation:

3y - x = 4

Substitute 2y - 6 for x:

3y - (2y - 6) = 4

Simplify by distributing the negative sign:

3y - 2y + 6 = 4

Combine like terms:

y + 6 = 4

Subtract 6 from both sides:

y = -2

Now that we have found the value of y, we can substitute it back into one of the equations to find the value of x. Let's use the first equation:

2y - x = 6

Substitute y = -2:

2(-2) - x = 6

Simplify:

-4 - x = 6

Add x to both sides:

-4 = x + 6

Subtract 6 from both sides:

-10 = x

Therefore, the solution to the system of equations 2y - x = 6 and 3y - x = 4 is x = -10 and y = -2.

User Wbharding
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