Question

Solve and graph the inequality 5x≤ 15. ​

Answer 1

To solve and graph the inequality 5x ≤ 15, we can start by isolating x on one side of the inequality sign.

Dividing both sides of the inequality by 5, we get:

x ≤ 3

This means that any value of x that is less than or equal to 3 will satisfy the inequality.

To graph the solution, we can plot a closed circle at x = 3 and shade the region to the left of the circle, including the circle itself. This is because any value of x less than or equal to 3 will make the inequality true, and the circle at x = 3 is included in the solution because x can be equal to 3.

So the graph of the solution to the inequality 5x ≤ 15 looks like:

o

/

/

-------o--------

x ≤ 3

The bolded region includes the closed circle at x = 3 and all the values of x to the left of it.

Answer 2

`\huge\text{Hey there!}`

`\mathsf{5x \leq 15}`

`\large\textsf{DIVIDE 5 to BOTH SIDES:}`

`\mathsf{(5x)/(5)\leq(15)/(5)}`

`\large\textsf{CANCEL out: \boxed{\bf (5)/(5)} because it give you 1}`

`\large\textsf{KEEP: \boxed{\bf (15)/(5)} because it help us know what is being compared to the x-value}`

`\mathsf{x \leq (15)/(5)}`

`\mathsf{x \leq 3}`

`\large\textsf{You have a(n) \boxed{\mathsf{closed}} shaded circle to your \boxed{\mathsf{left}}}`

`\huge\text{Therefore, your answer should be:}\\\\\huge\boxed{\mathsf{x \leq 3}}\huge\checkmark\\\\\huge\boxed{\large\huge{\textsf{You have a(n) \boxed{\mathsf{closed}} shaded circle to your \boxed{\mathsf{left}}}}}\huge\checkmark`

~
`\frak{Amphitrite1040:)}`