Question

What is the radius of a hemisphere with a volume of 4635 ft , to the nearest tenth of a foot?

Answer 1

The radius of a hemisphere with a volume of 4635 ft is approximately 11.3 ft, to the nearest tenth of a foot. This is because the volume of a hemisphere is equal to 2/3πr^3, where r is the radius. By rearranging this equation and solving for r, we can calculate the radius of the hemisphere.

Answer 2

The formula for the volume of a hemisphere is:

V = (2/3) * pi * r^3

where V is the volume of the hemisphere and r is the radius.

To find the radius of the hemisphere with a volume of 4635 ft, we can rearrange the formula as:

r = ((3 * V) / (2 * pi))^(1/3)

Substituting the given volume of 4635 ft, we get:

r = ((3 * 4635) / (2 * pi))^(1/3) = 16.68 ft (rounded to two decimal places)

Therefore, the radius of the hemisphere is approximately 16.7 ft to the nearest tenth of a foot.