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PLEASE HELP ASAP TY IN ADVANCE.

Use the thermal radiation laws and the Doppler shift law, you may also use the formula for the surface area of a sphere: A = 4 π r2

1. Thermal Radiation Laws
Find the thermal radiation emitted power and peak intensity wavelength for a sphere of radius
R = 6 370 000 m and temperature T = 288 K.

2. Doppler Calculations
a. In Hydrogen the transition from level 2 to level 1 has a rest wavelength of 121.6 nm. Find the speed and direction (toward or away from us) for a star in which this line appears at wavelength 120.7 nm.

User Ramr
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1 Answer

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1. Thermal Radiation Laws:

According to the Stefan-Boltzmann law, the total thermal radiation emitted power per unit surface area, P, of a blackbody (which absorbs all radiation that falls on it) is given by:

P = σT^4

where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W m^-2 K^-4) and T is the absolute temperature in Kelvin.

The Wien's displacement law states that the peak wavelength of thermal radiation emitted by a blackbody is given by:

λ_max = b/T

where b is Wien's displacement constant (2.898 x 10^-3 m K) and T is the absolute temperature in Kelvin.

The surface area of a sphere of radius R is given by:

A = 4πR^2

Therefore, the thermal radiation emitted power, P, of the sphere is:

P = σT^4 x A = σT^4 x 4πR^2

Substituting the values R = 6 370 000 m and T = 288 K, we get:

P = (5.67 x 10^-8 W m^-2 K^-4) x (288 K)^4 x 4π(6 370 000 m)^2 ≈ 3.99 x 10^17 W

The peak intensity wavelength, λ_max, of the thermal radiation emitted by the sphere is:

λ_max = (2.898 x 10^-3 m K) / 288 K ≈ 1.00 x 10^-5 m = 10 μm

Therefore, the sphere primarily emits infrared radiation.

2. Doppler Calculations:

The Doppler shift law relates the observed wavelength of radiation to the wavelength emitted by a source moving at a speed v relative to the observer:

λ_obs = λ_rest x (1 + v/c)

where λ_rest is the rest wavelength of the radiation, λ_obs is the observed wavelength, v is the speed of the source relative to the observer, and c is the speed of light.

In this case, the rest wavelength λ_rest is 121.6 nm, and the observed wavelength λ_obs is 120.7 nm. We can rearrange the Doppler shift equation to solve for v:

v = c x (λ_obs/λ_rest - 1)

Substituting the values, we get:

v = 3.00 x 10^8 m/s x (120.7 nm / 121.6 nm - 1) ≈ -2.99 x 10^5 m/s

The negative sign indicates that the star is moving away from us.

Therefore, the star is moving away from us at a speed of approximately 299,000 m/s (or 0.1% of the speed of light).

User Anze Jarni
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