Question

4) A beaker contains 0.53 mol of potassium bromide in 648.9 mL of water. An additional 648.9 mL of water is added. The number of moles of potassium bromide in the beaker is

Answer 1

1.06 mol

Step-by-step explanation

A beaker contains 0.53 mol of potassium bromide in 648.9 mL of water

An additional 648.9 mL of water is added implies the volume of the water will become (648+648)mL = 1297.8 mL

Therefore, the number of moles of potassium bromide in 1297.8 mL will be:

`\frac{0.53\text{ mol }*1297.8\text{ mL}}{648.9\text{ mL}}=1.06\text{ mol}`