Question

A ladder leans against the wall of a building. The ladder measures

48 inches and forms an angle of 70 with the ground. How far from
the ground, in inches, is the top of the ladder? How far from the
wall, in inches, is the base of the ladder? Round to two decimal
places as needed.

Answer 1

x=48sin 70

y=48sin 20 or 48cos 70

Explanation:

when you draw an appropraite diagram suitable for the question you realise that if forms a right hand triangle which 48in is the hypothenuese ,formed an angle of 70° due to elevation........

1. is also asking what is the height of the ladder when its to reaches the walll which is oposite in which is unknown

2. base of the ladder is the distance between the end side of the ladder on the floor and the wall

so we are to find height and base which is stated above

Using SOH CAH TOA

1. sin0=opp/hyp

2. cos0=adj/hyp

3. tan0=opp/adj

since we are finding height first we use 1

sin 70=x/48

x=sin 70×48

x=ans

sorry i dont calculator right now

using 2 to find base

cos 70=y/48

y=cos 70×48or 48cos 70

which can also be stated as 48×sin(90-70)=48×sin 20

Answer 2

Answer:
46.67 in
46.67 in
Explanation:
the value of the hypotenuse (length of the ladder) is given. We are to determine the value of the opposite side (distance from the ground) and adiacent side ( distance from the wall)
(distance from the ground = sin 45 = opposite /
hypotenuse
0.7071 = ×/66
x= 66 x 0.7071 = 46.67
distance from the wall = cos 45 = adjacent /
hypotenuse
0.7071 = ×/66
× = 66 x 0.7071 = 46.67