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An 21g sample of platinum metal increase in temperature by 4.90°C when 13.70J of heat are added. What is the specific heat

of platinum?

1 Answer

4 votes

Answer:

0.136 J/(g°C)

Step-by-step explanation:

We can use the formula for specific heat:

q = mcΔT

where q is the amount of heat added, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature.

Rearranging the formula, we get:

c = q / (m * ΔT)

Substituting the given values, we get:

c = 13.70 J / (21 g * 4.90°C)

c = 0.136 J/(g°C)

Therefore, the specific heat of platinum is 0.136 J/(g°C).


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