Question

What is the number of the molecules in the compound

3Al(C2H3O2)2

Answer 1

3.45 x 10^22 molecules

Step-by-step explanation:

To calculate the number of molecules in a compound, we need to know the number of moles of the compound first.

The molar mass of 3Al(C2H3O2)2 can be calculated as follows:

3 moles of Al (26.98 g/mol) = 80.94 g

6 moles of C (12.01 g/mol) = 72.06 g

12 moles of H (1.01 g/mol) = 12.12 g

12 moles of O (16.00 g/mol) = 192.00 g

Total molar mass = 357.12 g/mol

We can now find the number of moles in a given mass of the compound:

Number of moles = mass / molar mass

Number of moles = (3 x 26.98 g + 2 x 2 x 12.01 g + 2 x 3 x 1.01 g + 2 x 2 x 16.00 g) / 357.12 g/mol

Number of moles = 0.0573 moles

To calculate the number of molecules, we can use Avogadro's number, which is the number of particles in one mole of a substance.

Avogadro's number = 6.022 x 10^23 particles/mol

Therefore, the number of molecules in 0.0573 moles of 3Al(C2H3O2)2 is:

Number of molecules = number of moles x Avogadro's number

Number of molecules = 0.0573 moles x 6.022 x 10^23 molecules/mol

Number of molecules = 3.45 x 10^22 molecules

ALLEN

Answer 2

To determine the number of molecules in the compound 3Al(C2H3O2)2, we need to first determine the number of atoms in one molecule of this compound.

There are:

3 atoms of Al in each molecule of 3Al(C2H3O2)2

4 atoms of C in each molecule of C2H3O2 (2 atoms in each of the 2 acetate groups)

8 atoms of H in each molecule of C2H3O2 (4 atoms in each of the 2 acetate groups)

6 atoms of O in each molecule of C2H3O2 (3 atoms in each of the 2 acetate groups)

So one molecule of 3Al(C2H3O2)2 contains:

3 Al atoms

8 C atoms (4 from each of the two acetate groups)

24 H atoms (12 from each of the two acetate groups)

18 O atoms (9 from each of the two acetate groups)

Now we can use Avogadro's number, which is approximately 6.022 x 10^23 molecules per mole, to convert the number of atoms in one molecule to the number of molecules in the compound.

The total number of atoms in one molecule of 3Al(C2H3O2)2 is:

3 + 8 + 24 + 18 = 53

So one mole of 3Al(C2H3O2)2 contains 6.022 x 10^23 molecules, and the number of molecules in 3Al(C2H3O2)2 is:

(6.022 x 10^23 molecules/mol) x (1 mol / 53 atoms) x 3 x Avogadro's number = 3.23 x 10^23 molecules

Therefore, there are approximately 3.23 x 10^23 molecules in the compound 3Al(C2H3O2)2.