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How many atoms are in 4Pb(NO3)2

User Kevin Hogg
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2 Answers

7 votes

Answer:

36 atoms

Step-by-step explanation:

To determine the number of atoms in 4Pb(NO3)2, you first need to calculate the total number of atoms in one molecule of Pb(NO3)2 and then multiply by the coefficient 4.

The formula Pb(NO3)2 contains 1 lead (Pb) atom, 2 nitrogen (N) atoms, and 6 oxygen (O) atoms.

Therefore, the total number of atoms in one molecule of Pb(NO3)2 is:

1 (Pb atom) + 2 (N atoms) + 6 (O atoms) = 9 atoms

Multiplying by the coefficient 4 gives:

4 x 9 = 36

Therefore, there are 36 atoms in 4Pb(NO3)2.

ALLEN

User Clamum
by
7.4k points
5 votes

Answer:

4Pb(NO3)2, you can apply these steps:

The chemical formula is 4Pb(NO3)2.

The elements in the compound are Pb, N, and O.

The number of atoms of each element in one molecule of the compound are:

Pb: 1 (no subscript)

N: 2 (subscript after N in the parenthesis)

O: 6 (subscript after O in the parenthesis, multiplied by 2 because of the subscript outside the parenthesis)

The number of atoms of each element in the compound are:

Pb: 1 x 4 = 4 (multiplied by the coefficient 4)

N: 2 x 4 = 8 (multiplied by the coefficient 4)

O: 6 x 4 = 24 (multiplied by the coefficient 4)

Therefore, the total number of atoms in the compound are 4 + 8 + 24 = 36.

Step-by-step explanation:

User Tom Elliott
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6.6k points