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Imagine that you work in a crime lab, and the police bring to you a sample of a white powder that they believe to be cocaine (C17H2 NO4). When you carry out a combustion analysis on a 32 mg sample, you find that the sample contained 21.9 mg of carbon, 2.5 mg of hydrogen, 2.3 mg of nitrogen, and 5.3 mg of oxygen. What is the empirical formula for the white powder? Is this consistent with the molecular formula for cocaine?

Imagine that you work in a crime lab, and the police bring to you a sample of a white-example-1
User Quornian
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Answer:56

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User Shimanski Artem
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