Question

You will be making hanging flower baskets. The plants you have picked out are blooming annuals and

non-blooming annuals. The blooming annuals cost $3.20 each and the non-blooming annuals cost
$1.50 each. You bought a total of 24 plants for $49.60. How many of each type of plant did you buy?

Answer 1

Answer: Let's use some algebra to solve this problem.

Let's call the number of blooming annuals "x" and the number of non-blooming annuals "y".

We know that the total number of plants is 24, so we can write:

x + y = 24

We also know that the cost of each blooming annual is $3.20 and the cost of each non-blooming annual is $1.50, so we can write an equation for the total cost:

3.20x + 1.50y = 49.60

Now we have two equations with two variables, so we can solve for x and y.

Let's start by solving the first equation for one of the variables. For example, we can solve for y:

y = 24 - x

Now we can substitute this expression for y into the second equation and simplify:

3.20x + 1.50(24 - x) = 49.60

3.20x + 36 - 1.50x = 49.60

1.70x = 13.60

x = 8

So we bought 8 blooming annuals.

We can now use the first equation to find y:

8 + y = 24

y = 16

So we bought 16 non-blooming annuals.

Therefore, we bought 8 blooming annuals and 16 non-blooming annuals.

Explanation: