Question

A baggage handler drops your 9.20 kg suitcase onto a conveyor belt running at 2.60 m/s. The materials are such that μs = 0.490 and μk= 0.170. How far is your suitcase dragged before it is riding smoothly on the belt?

Answer 1

The suitcase is dragged approximately 4.62 meters before it is riding smoothly on the belt.

Step-by-step explanation:

To determine the distance the suitcase is dragged before it is riding smoothly on the belt, we need to calculate the frictional force acting on the suitcase. The frictional force can be calculated using the equation F_friction = μs * m * g, where μs is the coefficient of static friction, m is the mass of the suitcase, and g is the acceleration due to gravity. From the given information, μs = 0.490 and m = 9.20 kg.

Using the equation, F_friction = 0.490 * 9.20 * 9.8, we can calculate the frictional force to be 45.8 N.

The frictional force can also be expressed as F_friction = μk * m * g, where μk is the coefficient of kinetic friction. From the given information, μk = 0.170.

Using this equation, we can rearrange it to solve for the distance the suitcase is dragged: μk * m * g * d = F_friction * d, where d is the distance the suitcase is dragged.

Plugging in the values, 0.170 * 9.20 * 9.8 * d = 45.8 * d. Solving for d, we find that the suitcase is dragged approximately 4.62 meters before it is riding smoothly on the belt.