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If adult male heights are normally distributed with a mean of 180 cm and a standard deviation of 7 cm, how high should an aircraft lavatory door be to ensure that 99. 999 percent of adult males will not have to stop as they enter?.

User Anand Soni
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Answer: The lavatory door should be at least 212.2738 cm (or about 7 feet) high to ensure that 99.999% of adult males will not have to stop as they enter.

Explanation: To ensure that 99.999% of adult males will not have to stop as they enter the aircraft lavatory, we need to determine the height of the lavatory door such that only the tallest 0.001% of adult males will have to stop.

To find this height, we need to use the inverse normal cumulative distribution function, which gives the z-score corresponding to a given percentile. In this case, we want to find the z-score corresponding to the 99.999th percentile, which is given by:

z = invNorm(0.99999) ≈ 4.7534

where invNorm is the inverse normal cumulative distribution function.

We can then use the z-score formula to find the corresponding height:

z = (x - μ) / σ

where x is the height we want to find, μ is the mean height (180 cm), and σ is the standard deviation (7 cm). Solving for x, we get:

x = z * σ + μ

= 4.7534 * 7 + 180

≈ 212.2738 cm

User SexxLuthor
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