Question

I need the answer and how you solved it pleaseeeee

Answer 1

`\begin{gathered} Calculate\text{ the blocks for }BE, \\ \sin 65^(\circ)=(BD)/(BE) \\ \sin 65^(\circ)=(7)/(BE) \\ BE=7.7\text{ blocks} \\ \text{Now, calculate the blocks for AE, } \\ sin65^(\circ)=(AC)/(AE) \\ \sin 65^(\circ)=(10)/(AE) \\ AE=11 \\ So,\text{ the BA} \\ BA=AE-BE \\ BA=11-7.7 \\ BA=3.3\text{ blocks} \end{gathered}`