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Complex Roots

What are the roots of the equation x^2 + 2x + 65 = 0 in simplest a + bi form?

1 Answer

4 votes

Answer:


x=-1\pm8i

Explanation:

Complete the square of LHS and solve for x


x^2+2x+65=0\\x^2+2x+1=-64\\(x+1)^2=-64\\x+1=\pm8i\\x=-1\pm8i

User Ryanyuyu
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