Question

A cup of mass 125 g is at rest on a desk when it is accidentally knocked by a person’s arm. The cup accelerates in the direction that it is pushed at a rate of 0. 25 m/s2. How much force is applied by the arm that knocks the cup? Give your answer to two significant figures

Answer 1

x=0.031N to 2 significant figures

Step-by-step explanation:

F=ma

whereF=force,m=mass of the object, a=acceleration of the object

F=x, m=125g=125/1000=0.125kg , a=0.25m/s²

x=1/8×1/4

x=1/32

x=0.03125N

x=0.031N to 2 significant figures