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Complex Roots

What are the roots of the equation 25x^2 + 60x + 37 = 0 in simplest a + bi form?

User MPaulo
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2 Answers

7 votes

Step-by-step explanation:

The roots of the equation 25x^2 + 60x + 37 = 0 can be found using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 25, b = 60, and c = 37. Substituting these values into the formula, we get:

x = (-60 ± sqrt(60^2 - 4(25)(37))) / 2(25)

x = (-60 ± sqrt(3600 - 3700)) / 50

x = (-60 ± sqrt(-100)) / 50

Since the discriminant (b^2 - 4ac) is negative, the roots will be complex conjugates in the form a + bi, where a and b are real numbers. We can simplify the expression by factoring out the square root of -1 as i:

x = (-60 ± 10i) / 50

x = (-6 ± i) / 5

Therefore, the roots of the equation in simplest a + bi form are (-6 + i)/5 and (-6 - i)/5.

User Johannes Jensen
by
7.7k points
3 votes

Answer:


\displaystyle x=-(6)/(5)\pm(i)/(5)

Explanation:

Complete the square on LHS and solve for x


\displaystyle 25x^2+60x+37=0\\\\25x^2+60x+36=-1\\\\(5x+6)^2=-1\\\\5x+6=\pm i\\\\5x=-6\pm i\\\\x=-(6)/(5)\pm(i)/(5)

User SleepWalker
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8.3k points