Answer:
The nth row will have 100 seats when:
100 = 22 + (n-1)*6
Simplifying the equation gives:
n = 14.67
Since rows cannot have fractional values, the 15th row will have 100 seats
Explanation:
To solve this problem, we can use the formula for the arithmetic sequence, which is:
an = a1 + (n-1)d
where:
an = the nth term
a1 = the first term
d = the common difference between terms
n = the number of terms
In this problem, the first row has 22 seats, and the second row has 28 seats. The common difference between the number of seats in adjacent rows is 6, since the number of seats increases by 6 with each additional row. Therefore, we can write the formula for the number of seats in the nth row as:
an = 22 + (n-1)6
We want to find the row that has 100 seats, so we can set an equal to 100 and solve for n:
100 = 22 + (n-1)6
Simplifying this equation gives:
78 = 6n - 6
Adding 6 to both sides and dividing by 6 gives:
n = 14.67
However, since rows cannot have fractional values, we round up to the nearest whole number to get:
n = 15
Therefore, the 15th row will have 100 seats.