Question

A horizontal pipe of diameter 0.888 m has a

smooth constriction to a section of diameter
0.5328 m . The density of oil flowing in the
pipe is 821 kg/m3
.
If the pressure in the pipe is 7620 N/m
2
and
in the constricted section is 5715 N/m2
, what
is the rate at which oil is flowing? Answer in units of m3
/s.

Answer 1

of m3/s

A = π(D/2)2

Q1 = A1 * V1 = π * (0.888m / 2)2 * √[(7620 N/m2)/ (821 kg/m3)]
Q2 = A2 * V2 = π * (0.5328m / 2)2 * √[(5715 N/m2)/ (821 kg/m3)]

Q = Q1 - Q2 = 4.14 m3/s