Question

6. If the energy removed from an engine as heat during one cycle is 6.0 × 10³ J, how

much energy must be added to the engine during one cycle in order for it to
operate at 31 percent efficiency?

Answer 1

6.0 x 10³ / 0.31 = 19.35 x 10³ J

To solve this question, we need to use the formula for efficiency, which states that Efficiency = (Output Energy / Input Energy) x 100.

We know that the Output Energy is 6.0 × 10³ J, and we need to figure out the Input Energy. To find the Input Energy, we can rearrange the formula to Input Energy = (Output Energy / Efficiency) x 100.

Plugging in our values, we have Input Energy = (6.0 × 10³ J / 0.31) x 100 = 19.35 x 10³ J.

Therefore, the energy that must be added to the engine during one cycle in order for it to operate at 31 percent efficiency is 19.35 x 10³ J.